Escreva a matriz B=(bij)3×3, onde bij= i/j

3 linhas e 3 colunas

[b11  b12   b13]
[b21  b22   b23]
[b31  b32   b33]

bij = i/j
b11 = 1/1 = 1
b12 = 1/2
b13 = 1/3
b21 = 2/1 = 2
b22 = 2/2 = 1
b23 = 2/3
b31 = 3/1 = 3
b32 = 3/2
b33 = 3/3 = 1

        [1    1/2      1/3]
B =  [2      1       2/3]
        [3     3/2       1]​