Qual a função são afim abaixo, sabendo que f(1) = 5 e f(-3) =...

-x²+x-7=0
x²-x=-7
x²-x+1/4=-7+1/4
(x-1/2)²=-27/4
x-1/2=±√-27/2

S=∅

b)

x²/2+6x=0
x(x/2+6)=0
x=0

x/2+6=0
x/2=-6
x=-12

c)

-2x²-3x-2=0
x²+3x/2=-1
x²+3/2x+9/16=-1+9/16
(x+3/4)²=-7/16
x+3/4=±√-7/4

S=∅

d)

3x²+x-2=0
x²+x/3=2/3
x²+x/3+1/36=2/3+1/36
(x+1/6)²=25/36
x+1/6=±5/6
x=-1/6±5/6

x=2/3

x=-1

e)

-x²+8x-16=0
x²-8x+16=0
(x-4)²=0
x-4=0
x=4

     

​