o perimetro do triangulo abc sabendo que a(1,3) b (7,3) c (7,1...

Dab²=(Xb-Xa)²+(Yb-Ya)²

Dab²=(7-1)²+(3-3)²

Dab²=(6)² = 36

Dab=√36 = 6

Dbc²=(Xb-Xa)²+(Yb-Ya)²

Dbc²=(7-7)²+(11-3)²

Dbc²=(8)² =64

Dbc=√64 = 8

Dca²=(Xb-Xa)²+(Yb-Ya)²

Dca²=(1-7)²+(3-11)²

Dca²=(-6)²+(-8)²

Dca²=36+64

Dca²=100

Dca=√100 = 10

Perimetro do Triangulo ABC = 10 + 8 + 6 = 24